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What are the excluded values of the function? y=-2/5x+40

User Hieu Vo
by
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2 Answers

2 votes
In Terms of y:
y = -(2)/(5x) + 40
y = (-2) + (5x)40
y = 200x - 2/5x
In Terms of x:
y = -(2)/(5x) + 40
y = (-2) + (5x)40/5x
y = -2 + 5x • 40/5x
x = - 2/5y - 200
User NarasimhaTejaJ
by
6.9k points
1 vote

Answer:

Excluded values of the given function is -8.

Explanation:

Given Function is
y=(-2)/(5x+40)

We have to find Excluded values of the function.

We know that Values excluded from function are the values where functions cease to exist.

We are given a function with numerator and denominator.

So, When denominator becomes zero the function cease to exist.

Value of x when denominator become 0 are excluded from function.

Denominator from given function is 5x + 40

Put,

5x + 40 = 0

5x = 0 - 40

5x = -40


x=(-40)/(5)

x = -8

Therefore, Excluded values of the given function is -8.

User Jiro Matchonson
by
6.9k points
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