Question

A ball is thrown into the air with an upward velocity of 48 ft/s. Its height h in feet after t seconds is given by the function h = −16t2 + 48t + 6. In how many seconds does the ball reach its maximum height? Round to the nearest hundredth if necessary. What is the ball’s maximum height?

Answer 1

h = -16t • 2 + 48t + 6
h = -32t + 48t + 6
h = 16t + 6