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An alkane with the formula C6H14 can be prepared by hydrogenation of either of two precursor alkenes having the formula C6H12.

Write the structure of this alkane.
What is the Iupac name for the alkane.
Show on of the reactions that form this alkane.

The alkane is not hexane and it does not look like a six carbon chain.

User Garzanti
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2 Answers

2 votes
two precursor alkenes

H₃C CH₃
I I
H₂C=C-CH-CH₃ 2,3-dimethyl-1-butene

H₃C CH₃
I I
H₃C-CH=CH-CH₃ 2,3-dimethyl-2-butene


alkane

H₃C CH₃
I I
H₃C-CH-CH-CH₃ 2,3-dimethylbutane

H₃C CH₃ H₃C CH₃
I I I I
H₂C=C-CH-CH₃ + H₂ → H₃C-CH-CH-CH₃

H₃C CH₃ H₃C CH₃
I I I I
H₂C-C=CH-CH₃ + H₂ → H₃C-CH-CH-CH₃

User Vasmay
by
6.1k points
4 votes

Answer:

2-methylpentane

Step-by-step explanation:

Hello,

On the attached document, you will find the solution for this exercise. It is important for you to notice that at the reactions there are two possible precursors, 2-methylpentene and 4-methylpentene which are suitable to form 2-methylpentane via hydrogenation.

Best regards.

An alkane with the formula C6H14 can be prepared by hydrogenation of either of two-example-1
User Eric Duffett
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