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The equation of the graphed line in point-slope form is ____

y-0=-3/5(x-3),
3y=-5(x-3),
y-3=-3/5(x-0)

and its equation in slope-intercept form is ____
y=-9/5x+3/5
5y=-3(x-3)
y= -3/5x+9/5

The equation of the graphed line in point-slope form is ____ y-0=-3/5(x-3), 3y=-5(x-example-1
User Wiseindy
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2 Answers

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Answer:

8

Explanation:

help

User Times
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hello :
The equation of the graphed line in point-slope form is : y-0=-3/5(x-3)
because ; when : x=3 y=0 passes by : (3,0)
when : x = -2 y = 3 passes by : (-2, 3)

and its equation in slope-intercept form is : y= -3/5x+9/5
because :
y-0=-3/5(x-3) : y = -3/5x +9/5
User Ribena
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