Question

If cacl2 is dissolved in water, what can be said about the concentration of the ca2+ ion?

Answer 1

Dissolving CaCl2 in water results in a stoichiometric amount of Ca2+ ions, with one mole of CaCl2 producing one mole of Ca2+ ions, equating to 2 equivalents due to the +2 charge of calcium.

Step-by-step explanation:

When Cacl2 is dissolved in water, the concentration of the Ca2+ ion will depend on the stoichiometry of the dissolution process. For every one mole of CaCl2 that dissolves, two moles of Cl- ions and one mole of Ca2+ ions are produced in solution. Therefore, if one mole of CaCl2 is dissolved, there will be one mole of Ca2+ ions present in the solution, which translates to 2 equivalents (Eq) of Ca2+ ions since calcium has a +2 charge.

Answer 2

The concentration of
`Cl^(-)` ions will be double than that of
`Ca^(2+)`

Calcium chloride -
`CaCl_(2)` has one Ca atom and 2 atom of chlorine.

When it is dissolved in water, it disassociates into
`Ca^(2+)` and
`2Cl^(-)`

Thus, the concentration of
`Cl^(-)` ions will be double than that of
`Ca^(2+)`

Or we can say the ratio of
`Cl^(-)` :
`Ca^(2+)` = 2:1