Question

Simplify the following


`\sqrt{98]`

`\sqrt{16 b^(5) }`

`3√(5m) x 4\sqrt{(1)/(5) m3}`

`√(26x2)`

Answer 1

`→ √(98) = √(7 * 7 *2) = 7 √(2)✓`

`→ \sqrt{ 16{b}^(5) }= \sqrt{4 * 4 * {b}^(5) } = 4 {b}^{ (5)/(2) } ✓`

`→3 \sqrt{5 mx^(4) } \sqrt{ (1)/(5) {m}^(3)} = 3 \sqrt{5 * (1)/(5) {m}^(4) {x}^(4) } = 3 {m}^(2) {x}^(2) ✓`

`→\sqrt{26 {x}^(2) } = √(26) x✓`

Answer 2

Explanation:

Simplify:

• 
  `√(98) = √(49*2) = √(7^2*2) = 7√(2)`

• 
  `√(16b^5) = √(4^2(b^2)^2b) = 4b^2√(b)`

• 
  `3√(5mx^4) √(1/5m^3) = 3√(5*1/5*m^4x^4) = 3√((m^2)^2(x^2)^2) = 3m^2x^2`

• 
  `√(26x^2) = x√(26)`