Δ ABC is an isosceles right triangle:∠ ABC =∠BCA = V45°
Δ ACE is also a right triangle (inscribed in half a circle.
The sum of its angles = 180° and ∠CAE + ∠ACE = 90 ;
∠ CAE + 57° *given) = 90°, then ∠ CAE = 33°
CALCULATE ∠ BAE:
∠ BAE = ∠BAC + ∠CAE
∠BAE = 45° + 33° = 78°