Question

Can somebody explain how to do this problem?

Answer 1

Let e^-3x be u,
10u^-2=5u
10/u^2=5u
5u^3=10
u^3=10/5
u=1.25992105
e^-3x=1.25992105
-3x=0.2310490602
x=-0.0770
Method 2
10e^6x=5e^-3x
10e^6x-5e^-3x=0
5e^-3x(2e^9x-1)=0
2e^9x-1=0
2e^9x=1
e^9x=1/2
9x=loge1/2
x=(loge1/2)/9
=-0.0770

Answer 2

physicsforums.com has step by step explanation but here is example
y=-9e-19x^6+2e-14x^5-2e-10x^4+1e-06x^3-0.0027x^2+3.5222x-1656.5
shorthand =(10^-9)-(19x*x^6)etc..... go to physics sight it breaks different examples down. sorry i couldnt give u direct answer but i always have to find example problems to walk me thru it as needed