Question

How would you write 0x+19y=38 in slope-intercept form?

Answer 1

Basically, we need to isolate y

Assuming 0 is unnecessary:

x + 19y = 38
19y = -x + 38

`y= (-x+38)/(19)`

`y= -(x)/(19) + (38)/(19)`

`y= -(x)/(19) +2`



Assuming that 0 is necessary:

0x+19y = 38

0•x is equivalent to 0 so that cancels out x leaving us with

19y = 38

y = 38/19

y = 2


If the 0 is necessary, your answer is y = 2.
If the 0 is unnecessary, your answer is y = -(x/19)+2