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A line passes through (-3, -2) and is perpendicular to 3x - 2y = 7.

What is the equation of the line in slope-intercept form?

2 Answers

7 votes
When graphing this, the answer that I derived was y = -2/3x -4
User AltDan
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3 votes

Answer:
y=(-2)/(3)x-4

Explanation:

The given equation of line :


3x-2y=7\\\\\Rightarrow\ y=(3)/(2)x-(7)/(2), comparing to the standard equation of line
y=mx+c, the slope of line =
m= (3)/(2)

Also, when two lines are perpendicular , then the product of their slope is -1.

Therefore, the slope of line perpendicular to the given line =
(-1)/((3)/(2))=(-2)/(3)

Now, the equation of the line passing from (-3, -2) with slope
(-2)/(3) is given by ;-


(y-(-2))=(-2)/(3)(x-(-3))\\\\\Rightarrow\ y=(-2)/(3)(x+3)-2\\\\\Rightarrow\ y=(-2)/(3)x-4

Hence, the equation of the line in slope-intercept form L


y=(-2)/(3)x-4

User Rdnobrega
by
7.8k points

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