Question

For a moving object, the force acting on the object varies directly with the object's acceleration. When a force of 40 N acts on a certain object, the acceleration

of the object is 10 m/s. If the acceleration of the object becomes 6 m/s?, what is the force?

Answer 1

New force = 24 N

Explanation:

The force acting on the object varies directly with the object's acceleration

i.e.

`(F_1)/(F_2)=(a_1)/(a_2)` ...(1)

We have,

F₁ = 40 N, a₁ = 10 m/s², a₂ = 6 m/s₂, F₂ =?

Put all the values in equation (1).

`F_2=(F_1a_2)/(a_1)\\\\F_2=(40* 6)/(10)\\\\F_2=24\ N`

So, the new force becomes 24 N.