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What is the value of x in the equation (1/4)x^4-x^2=(5/4)

User Rich Henry
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1 Answer

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(1/2)x^2 = T

T^2 - 2T - 5/4 = 0
4T^2 - 8T - 5 = 0
(2T-5)(2T+1) = 0
T = 5/2 >>> (1/2)x^2 = 5/2
x = root(5)
x = -root (5)
T = -1/2 >>> no root (1/2x^2 = pozitive)


Good Luck :D
User Mitja Gomboc
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