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The sum of one-third of a number and three-fourths of the number exceeds that number by one. Which equation could be used to find the number? n = n + 1 n + n = n - 1 n + n = n + 1

User Guy Blanc
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2 Answers

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(n)/(3) + (3n)/(4) = n+1

4n + 9n = n+1

13n = n+1

13n-n = 1

12n = 1

User Karol Berezicki
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8.1k points
3 votes

Answer:


(n)/(3) +
(3n)/(4) = n +1.

Number = 12.

Explanation:

Given : The sum of one-third of a number and three-fourths of the number exceeds that number by one.

To find : Which equation could be used to find the number.

Solution : We have given a statement

Let a number = n

According to question

One third of a number =
(n)/(3).

Three - fourths of the number =
(3n)/(4).

Sum of their is exceeds that number by one.


(n)/(3) +
(3n)/(4) = n +1.

Taking common denominator


(4n+9n)/(12) = n+1 .


(13n)/(12) = n+1.

On subtracting n both sides.


(13n)/(12) -n = 1

Taking common denominator


(13n -12n)/(12) = 1


(n)/(12) = 1

On multiplying by 12 both sides

n= 12.

Therefore,
(n)/(3) +
(3n)/(4) = n +1.

Number = 12.

User Ensonic
by
8.4k points

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