192k views
2 votes
(Sinx+cosx)/cosx*sinx

User Quanguyen
by
7.6k points

1 Answer

2 votes

(sinx+cosx)/cosx*sinx= (sin(x)+cos(x))/(cos(x).sin(x)) =(sin(x))/(cos(x).sin(x))+(cos(x))/(cos(x).sin(x))\\~\\~\\=(1)/(cos(x))+(1)/(sin(x))=sec(x)+cosec(x)

I hope that helps!



User Brian Huffman
by
8.6k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories