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Use the method of cylindrical shells to find the volume of the solid obtained by rotating the region bounded by the given curves about the x-axis. y = x3/2, y = 8, x = 0

User KyluAce
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solve for the value of x such that f(x)=8
imma assume it is y=x^(3/2)
so
solve 8=x^(3/2)
x=4
so integrate from x=0 to x=4

\pi \int\limits^4_0 {(x^ (3)/(2))^2 } \, dx is the area

\pi \int\limits^4_0 {x^3 } \, dx=

\pi [ (1)/(4)x^4 ]^4_0=

\pi (4^3)=
64π cubic units
User Zhorov
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