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5 votes
Sketch one cycle of the cosine function y= – cos 3θ

User Danuofr
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2 Answers

3 votes
hmmm same as the other you posted... is the graph of y= cos(θ), but with a negative Amplitude of -1, and a B component of 3

let's check the period again
\bf \cfrac{2\pi }{B}\iff \cfrac{2\pi }{3}

so, is the same graph, with a period of
\bf \cfrac{2\pi }{3} and the negative amplitude will simply, retain the same midline, but the graph will be turned upside-down
User Juan Campa
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7.9k points
3 votes

Answer:

Refer the attached graph

Explanation:

Given : Function
y=-cos3\theta

To Sketch the given function :

General form:
y=\alpha cos(\beta\theta)

where
\alpha=amplitude and
(2\pi)/(\beta) = period

According to question,
y=-cos3\theta


\alpha=-1 and
(2\pi)/(3) = period

From
(0,(2\pi )/(3) ) cosine function sketch refer the attached graph .


Sketch one cycle of the cosine function y= – cos 3θ-example-1
User Knut
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8.1k points