89.7k views
1 vote
A triangle has the vertices: A(-4,7), B(-3, 5) and C(8, -1).

What is the length of the perimeter of the triangle?

1 Answer

1 vote
You can find the length of the sides using the a result of the Pythagorean Theorem. Each side is:

s^2=(x2-x1)^2+(y2-y1)^2 so you have:

s1^2=(-3--4)^2+(5-7)^2

s1^2=1+4

s1=√5

s2^2=(8--3)^2+(-1-5)^2

s2^2=121+36

s2=√157

s3^2=(8--4)^2+(-1-7)^2

s3^2=144+64

s3=√208

The perimeter is:

p=s1+s2+s3

p=√5+√157+√208 units

p≈29.19 units (to nearest hundredth)
User Oleg Kodysh
by
8.5k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories