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A triangle has the vertices: A(-4,7), B(-3, 5) and C(8, -1). What is the length of the perimeter of the triangle?
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Feb 22, 2018
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A triangle has the vertices: A(-4,7), B(-3, 5) and C(8, -1).
What is the length of the perimeter of the triangle?
Mathematics
high-school
Slava Shpitalny
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Slava Shpitalny
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You can find the length of the sides using the a result of the Pythagorean Theorem. Each side is:
s^2=(x2-x1)^2+(y2-y1)^2 so you have:
s1^2=(-3--4)^2+(5-7)^2
s1^2=1+4
s1=√5
s2^2=(8--3)^2+(-1-5)^2
s2^2=121+36
s2=√157
s3^2=(8--4)^2+(-1-7)^2
s3^2=144+64
s3=√208
The perimeter is:
p=s1+s2+s3
p=√5+√157+√208 units
p≈29.19 units (to nearest hundredth)
Oleg Kodysh
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Feb 27, 2018
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Oleg Kodysh
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