Question

Find 2x2 − 2z4 + y2 − x2 + z4 if x = −4, y = 3, and z = 2

Answer 1

Hello,
2x^2-2z^4+y^2-x^2+z^4
Substitute x=-4, y=3, and z=2 into this expression

2(-4)^2-2(2)^4+3^2-(-4)^2+2^4
=2(16)-2(16)+9-16+16
=32-32+9-16-16
=0+9+0
=9. As a result, 9 is your final answer. Hope it help!

Answer 2

Assuming that the numbers after the variables are exponents: 2(-4)^2 - 2(2)^4 + (3)^2 - (-4)^2 + (2)^4 would be equivalent to

32 - 32 + 9 - 16 + 16

The 32's cancel out and so do the 16's, leaving you with:

9