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Logan measured a line to be 7.4 inches long. If the actual length of the line is 7.7 inches, then what was the percent error of the measurement, to the nearest tenth of a percent?​
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Logan measured a line to be 7.4 inches long. If the actual length of the line is 7.7 inches, then what was the percent error of the measurement, to the nearest tenth of a percent?​

User Ashish Bindal
by
3.6k points

2 Answers

2 votes
I think it’s 3.8% i’m not sure tho
User Zexks Marquise
by
3.5k points
5 votes

Answer:

3.9%

Explanation:

Percentage error


= (7.7 - 7.4)/(7.7) * 100 \\ \\ = (0.3)/(7.7) * 100 \\ \\ = (300)/(77) \\ \\ = 3.8961039 \\ \\ = 3.9 \%

User Narendra Jadhav
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4.1k points
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