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Using the equation, 4Fe + 3O2 2Fe2O3, if 6 moles of iron (III) oxide were produced, how many moles of iron would be required?

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The answer is: "Twelve (12) moles of Fe (iron) would be required."
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or:
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The answer is: "12" .
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Note: The balanced chemical equation is given:
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4 Fe + 3 O₂ → 2 Fe₂O₃
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The product is: 2 moles of FeO ; that is, "2 moles of iron (III) oxide" .
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If SIX (6) moles of iron oxide were produced, that would be "3 (three) times the number of moles of iron oxide produced (3 TIMES 2) ;
since: "6 ÷ 2 = 3" ; and since the equation is balanced.
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→ So we want to find the number of moles of "iron (Fe)" needed in such a situation. In the balanced chemical, we have "4 Fe" (that is, "FOUR (4) moles of iron") ; so we multiply that number by "3", proportionally:
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4 (moles Fe) * (3) = 12 (moles Fe) .
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User William Leara
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