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The sum of three numbers is 131. The second of three numbers is seven more than twice the first. The third number is 12 less than the first. What equation can be used to solve the problem?
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The sum of three numbers is 131. The second of three numbers is seven more than twice the first. The third number is 12 less than the first. What equation can be used to solve the problem?

User Darshit Patel
by
8.3k points

2 Answers

6 votes

Answer:

x + (2x + 7) + (x – 12) = 131

Explanation:

User Alptugay
by
8.7k points
3 votes
x + 2x+7 + x- 12 = 131
User Najm
by
7.9k points
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