Question

A gas is contained in a 5.0–liter container at a pressure of 100 kPa. What size container would be required to contain the gas at a pressure of 50 kPa, assuming the temperature remains constant?

Answer 1

C.

a 10.0–liter container

Step-by-step explanation:

P1V1=P2V2

(100)(5)=(50)V2

500=50V2

V2=10L

Answer 2

when volume and pressures are given, it means we need to use Boyles' law formula--> P1V1 = P2V2

P1= 100 kPa
V1= 5.0 L
P2= 50 kPa
V2= ???

let's plug in the values.

(100 x 5.0) = (50 x V2)

V2= 10 L