Question

Question 3 of 10

An engine performs 6400 J of work on a motorbike. The motorbike and rider
have a combined mass of 200 kg. If the bike started at rest, what is the speed
of the bike after the work is performed?

Answer 1

8 m/s

Step-by-step explanation:

KE Formula: KE = 1/2mv^2

Kinetic Energy is equal to energy, J.

6400 = 1/2 * 200 * V^2

1/2 * 200 = 100

6400 = 100 * V^2

6400/100 = V^2

64 = V^2

Square root both sides

Speed is 8 m/s