If 0.78% of a radioactive substance remains, then how many half-lives have passed? 3 7 6 4

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asked Aug 18, 2018 164k views

2 Answers

Jacktose · Answer 1 · 2018-08-24T08:51:02+0000

The answer would be 7 because of this solution:

You divide (1|2) and then divide it by 7.

The answer should be 0.78% of the remaining half-lives after 7. Because of the remaining radioactive substance that happens during that 0.78 percentage.

If 0.78% of a radioactive substance remains, then how many half-lives have passed? 3 7 6 4

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