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The sum of the two digits of a number is 16. The number formed by reversing the digits is 18 more than the original number. Determine the original number. Let t = the tens digit, u = the units digit, and u + t = 16. Which of the following equations would complete the system?

9t - 9u = 18
9u - 9t = 18
tu = ut + 18

User Ifeanyi
by
7.8k points

2 Answers

1 vote
9t-9u=18 is ur answer
User Mogli
by
6.9k points
5 votes

Answer:


9u-9t=18

Explanation:

The equation that completes the system is:


9u-9t=18

First, we have to remember that tens value 10 units per digit, and units value one uni per digit. So, the number of the problem would be expressed like:


10t+u

Now, the problem states that if the number is reversed its formed another number which is 18 units more than the original, that would be expressed like:


10u+t=10t+u+18

Solving this relation, we have:


10u-u=10t-t+18\\9u=9t+18\\9u-9t=18

Therefore, the expression that complete the system is the second equation.

User Magdeline
by
8.3k points
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