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40 votes
How can i solve this provelm and round it to the nearest thenth of a centimeter

How can i solve this provelm and round it to the nearest thenth of a centimeter-example-1
User Juliett
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1 Answer

22 votes
22 votes

Applying Pythagoras' theorem;


hypotenuse^2=\text{ x}^2+y^2
158^2=83^2+z^2
\begin{gathered} 24964=6889+z^2 \\ z^2=24964-6889 \\ z^2=18075 \\ z=√(18075) \\ z=134.4cn \end{gathered}

User Shkaper
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