Question

HELP! PROBABILITY!

Emil would like to estimate the probability of 2 or more heads coming up in 3 coin flips. To do this, he has a computer randomly select 0 or 1 three times, with 0 representing heads and 1 representing tails. The results of 12 trials are shown in the table.

111 011 000 010
100 111 010 111
111 101 000 111

What is Emil's estimated probability, based on this simulation?

i think its 5/12

Answer 1

you are correct its 5/12

Answer 2

Estimated probability
`P=(5)/(12)`

Explanation:

In this question Emil estimates the probability of 2 or more heads coming up in 3 coin flips.

He has a computer which randomly selects 0 or 1 three times, with 0 representing heads and 1 as tails.

From the results shown we will select the preferred events of getting 2 or more heads, means results having 2 zeros or more than 2 zeros.

Number of preferred events are = 5

And total events are = 12

Therefore estimated probability =
`P=\frac{\text{Preferred events}}{\text{Total events}}`

Probability
`P=(5)/(12)`

Therefore answer is
`P=(5)/(12)`