Question

A six character secret code can begin with any two of five vowels and end with four numerals from 0 to 9. If the numerals cannot repeat, how many secret codes can be formed?

(I need this answer, put the question up an hour ago and nobody even looked at it, please, I made it worth 27 points now)

Answer 1

2 of 5 vowles
can repeat vowels but now numbers

so the first slot is 5 choices
2nd is 5 choices

then 4 numerals
10 numerlas for 1st slot
9 for 2nd (1 less choice)
8 for 3rd
7 for 4th

so
5*5*10*9*8*7=126000 secret codes