Question

What is the product? 4k+2/k^2-4*k-2/2k+1

Answer 1

1. Factor: 2(2k+1)(k-2)/(k-2)(k+2)(2k+1)
2. Cancel out like terms: 2/(k+2)
3. Final answer: 2/(k+2)

Answer 2

Answer:
`(2)/(k+2)`

Step-by-step explanation:

Firstly, we will split the denominator
`k^(2) -4 =(k-2)(k+2)` by the formula of (
`a^(2) -b^(2)`) = (a-b)(a+b)

then, the given terms
`(4k+2)/(k^(2)-4) * (k-2)/(2k+1)`

will become
`(4k+2)/((k-2)(k+2)) *(k-2)/(2k+1)`

now, cancel the common factor that is k-2 we get

`(4k+2)/((k+2)(2k+1))`

Now taking 2 as common from 4k+2 we will get 2(2k+1)

we will get
`(2(2k+1))/((k+2)(2k+1))` common factor will get cancelled which is 2k+1

Hence, we will finally get
`(2)/(k+2)`