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Which is the minimum value of the function y=x^2+8x+7
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2 votes
Which is the minimum value of the function y=x^2+8x+7

User Mimere
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2 Answers

5 votes
You can do this by completing the square.
Y=x^2 + 8x + 7
= (x+4)^2 -16+7
= (x+4)^2 - 9

Minimum value = -9
User Tolu
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8.4k points
4 votes
The minimum value of the function is (-4, -9).
User SorcyCat
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8.5k points
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