Question

What is the pH of a solution containing a 1.00 x 10−4 M solution of HCl?

A. 1
B. 4
C. 1 x 10^4
D. 1 x 10^4

Answer 1

HCl = H⁺ + Cl⁻

c(HCl)=1.00*10⁻⁴ mol/l

[H⁺]=c(HCl)=1.00*10⁻⁴ mol/l

pH=-lg[H⁺]

pH=-lg(1.00*10⁻⁴)=4

pH=4