Simplify: 1) (8x^2y^2) * (2xy^4) 2) (2x^2)^4 3) (4x^2y^5)^3 4) 6n^3m^4/ 24nm^8 5) 12x^10y^14/ 4x^6y^11 6) (-4xy^2z^-2/x^3^-1)^2 7) (x^2y^3)^0

asked Jun 17, 2018 93.7k views

4 votes

Simplify:

1) (8x^2y^2) * (2xy^4)
2) (2x^2)^4
3) (4x^2y^5)^3
4) 6n^3m^4/ 24nm^8
5) 12x^10y^14/ 4x^6y^11
6) (-4xy^2z^-2/x^3^-1)^2
7) (x^2y^3)^0

by Wsn

6.1k points

Please log in or register to add a comment.

2 votes

$16x^3y^6 \\ 16x^8 \\ 64x^6y^(15)\\ (n^2)/(4m^4) \\3x^4y^3\\ IDK \\1$
There ya go! I'll adjust number 6 once you rewrite it.

6.2k points

3 votes

one is 16x³y⁶

two is 16x⁸

three is 64x⁶y¹⁵

four is ???

five is ???

six is ???

seven is 1

Felix ZY answered Jun 23, 2018

5.9k points

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

6.6m questions

8.8m answers