Question

Devon and his friends bought strawberry wafers for $3 per packet and chocolate wafers for $1 per packet at a carnival. They spent a total of $30 to buy a total of 22 packets of wafers of the two varieties.

Part A: Write a system of equations that can be solved to find the number of packets of strawberry wafers and the number of packets of chocolate wafers that Devon and his friends bought at the carnival. Define the variables used in the equations. (5 points)

Part B: How many packets of chocolate wafers and strawberry wafers did they buy? Explain how you got the answer and why you selected a particular method to get the answer. (5 points)

Answer 1

Devon and his friends bought 4 packets of strawberry wafers and 18 packets of chocolate wafers.

Step-by-step explanation:

Part A: Let x represent the number of packets of strawberry wafers and y represent the number of packets of chocolate wafers. Based on the given information, we can set up the following system of equations:

• x + y = 22 (Equation 1) - since Devon and his friends bought a total of 22 packets of wafers
• 3x + 1y = 30 (Equation 2) - since the cost of strawberry wafers is $3 per packet and the cost of chocolate wafers is $1 per packet

Part B: To solve the system of equations, we can use substitution or elimination. Using elimination, we can multiply Equation 1 by 3 and subtract Equation 2 from it:

(3x + 3y) - (3x + y) = 66 - 30

2y = 36

y = 18

Substituting the value of y back into Equation 1, we get:

x + 18 = 22

x = 4

Therefore, Devon and his friends bought 4 packets of strawberry wafers and 18 packets of chocolate wafers.

Answer 2

s+c=total wafers
3*s+1*c=total cost