Iggy, this is the solution:
First metall alloy = 15% Copper
Second metal alloy = 65% Copper
60 kg of the mix = 60 * 0.55 Copper = 33 kilograms of copper
Let x to represent the number of kilograms of the first alloy
Let y to represent the number of kilograms of the second alloy
x + y = 60
x = 60 - y
For solving for y, we have:
0.15x + 0.65y = 60 * 0.55
0.15 (60 - y) + 0.65y = 33
9 - 0.15y + 0.65y = 33
9 + 0.5y = 33
Subtracting 9 at both sides:
9 + 0.5y - 9 = 33 - 9
0.5y = 24
Multiplying by 2 at both sides:
0.5y * 2 = 24 * 2
y = 48 (The metalworker needs 48 kilograms of the second alloy)
For solving for x, we have:
x + y = 60
x + 48 = 60
x = 60 - 48
x = 12 (The metalworker needs 12 kilograms of the first alloy)