Question

9_xusx²-24-63x 245 x-tu

Answer 1

`\begin{gathered} (x+5)/(x^2-2x-63)+(x^2+3)/(x^2+5x-14) \\ \text{expand the denominators} \\ x^2-2x-63=(x+7)(x-9) \\ x^2+5x-14=(x+7)(x-2) \\ (x+5)/((x+7)(x-9))+(x^2+3)/((x+7)(x-2)) \\ ((x+5)(x-2)+(x-9)(x^2+3))/((x+7)(x-9)(x-2)) \\ \frac{x^2-2x+5x-10+x^{\text{ 3}}+3x-9x^2-27}{(x+7)(x-9)(x-2)} \\ (x^3-8x^2+6x-37)/((x+7)(x-9)(x-2)) \\ \end{gathered}`