Question

What is the product? x^2-16/2x+8 * x^3-2x^2+x/x^2+3x-42

Answer 1

Factor to get


`(x(x-4)(x-1)(x-1))/(2(x^2+3x-42))`

Answer 2

Answer with explanation:

`\rightarrow(x^2-16)/(2x+8) * (x^3-2 x^2+x)/(x^2+3 x-42)\\\\=((x-4)(x+4))/(2* (x+4)) * (x * (x^2-2 x+1))/(x^2+3 x-42)\\\\=(x(x-4)(x-1)^2)/(2* (x^2+3 x-42))\\\\\text{Used the Identity}}\\\\a^2-b^2=(a-b)(a+b)\\\\(a-b)^2=a^2-2 a b+b^2`