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5 votes
Suppose you have a mean standardized score of 1500 points with a standard deviation of 150 points. This data is normally distributed. What is the z-score of 1750 points?

2 Answers

4 votes

Answer:

The z-score is 1.667. ( approx )

Explanation:

In normal distribution,

The z-score or standard score of a score x is,


z=(x-\mu)/(\sigma)

Where,


\mu is mean,


\sigma is standard deviation,

Here,


\mu = 1500


\sigma = 150

Hence, the z-score of 1750 points is,


z=(1750-1500)/(150)


=(250)/(150)


\approx 1.667

User Ncatnow
by
7.9k points
1 vote
Mean, μ=1500
Standard Deviation, σ=150
X=1750

Then

z-score= (1750-1500)/(150)

z-score=1.7 (rounded to one decimal place)


User Uthman
by
7.9k points

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