Question

A flashlight has a resistance of 2.4 . What voltage is applied by the batteries if the current in the circuit is

2.5 A?
0.96
V 1.0
V 4.9
V 6.0 V

Answer 1

using V=IR, I is 2.5 and R is 2.4
therefore answer is 2.4 multiply by 2.5 which is equal to 6v

Answer 2

Answer : The voltage applied by the batteries is, 6.0 V

Solution : Given,

Resistance of flashlight = 2.4 ohm

Current in the circuit = 2.5 Ampere

Formula used :

`V=IR`

where,

V = applied voltage

I = current in the circuit

R = resistance of light

Now put all the given values in the above formula, we get

`V=(2.5A)* (2.4ohm)=6volt=6V`

Therefore, the voltage applied by the batteries is, 6.0 V