Question

A bag has 1 orange lollipop, two red lollipops, 7 Green lollipops, 6 blue lollipops and 4 speckled lollipops. You randomly pull a lollipop from the bag put it back and pull out another one.What is the probability of getting a green and then a green? Write your answer as a decimal rounded to the nearest hundredth.

Answer 1

Given:

A bag has 1 orange lollipop, 2 red lollipops, 7 Green lollipops, 6 blue lollipops and 4 speckled lollipops.

To find:

The probability of getting a green and then a green.

Step-by-step explanation:

Sample space

`\begin{gathered} n(S)=1+2+7+6+4 \\ n(S)=20 \end{gathered}`

Let A be the event of getting a green lollipop.

`\begin{gathered} n(A)=7 \\ P(A)=(n(A))/(n(S)) \\ =(7)/(20) \end{gathered}`

Let B be the event of getting a green lollipop afterpout it back from the first even.

`\begin{gathered} n(B)=7 \\ P(B)=(7)/(20) \end{gathered}`

Therefore, The probability of getting a green and then a green is

`\begin{gathered} P(A\cap B)=P(A)\cdot P(B) \\ =(7)/(20)\cdot(7)/(20) \\ =(49)/(400) \\ =0.12 \end{gathered}`