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A restaurant is at 75% cpacity with 120 patrons. How many people would be in the restaurants at 100% capacity?
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A restaurant is at 75% cpacity with 120 patrons. How many people would be in the restaurants at 100% capacity?

User Joo Beck
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2 Answers

6 votes
160 patrons would be the 100% capacity
User Sam Grondahl
by
8.8k points
6 votes
75%=120

1%=120/75

100% = 1% x 100

100%=(120/75)x100

100%= 160


User Mayank Ahuja
by
8.4k points
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