Register
A restaurant is at 75% cpacity with 120 patrons. How many people would be in the restaurants at 100% capacity?
286 views
2 votes
A restaurant is at 75% cpacity with 120 patrons. How many people would be in the restaurants at 100% capacity?

User Joo Beck
by
7.8k points

2 Answers

6 votes
160 patrons would be the 100% capacity
User Sam Grondahl
by
8.8k points
6 votes
75%=120

1%=120/75

100% = 1% x 100

100%=(120/75)x100

100%= 160


User Mayank Ahuja
by
8.4k points
Ask a Question
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.5m questions

12.2m answers

Other Questions

How do you can you solve this problem 37 + y = 87; y =
What is .725 as a fraction
How do you estimate of 4 5/8 X 1/3
A bathtub is being filled with water. After 3 minutes 4/5 of the tub is full. Assuming the rate is constant, how much longer will it take to fill the tub?
Write words to match the expression. 24- ( 6+3)
Link Copied!