Which value of x would make NO II KJ? 1 6 8 10

Question

asked Nov 9, 2018 55.7k views

2 Answers

Anentropic · Answer 1 · 2018-11-13T19:13:12+0000

we know that

If NO II KJ

then

triangles LKJ and LNO are similar and the ratio of the corresponding sides are equals

so

(LO)/(LN)= (LJ)/(LK)

we have

$LO=(x-4)\ in$

$LN=(x-3)\ in$

$LJ=LO+OJ=(x-4)+x=2x-4\ in$

$LK=LN+NK=(x-3)+(x-2)=2x-1\ in$

substitute

$(x-4)/(x-3)=(2x-4)/(2x-1) \\ \\(x-4)*(2x-1)=(2x-4)*(x-3)\\ \\2x^(2) -x-8x+4=2x^(2) -6x-4x+12\\ \\-9x+10x=12-4\\ \\ x=8\ units$

therefore

the answer is the option

$x=8\ units$