Question

A tank is losing water at a rate of 3 gallons per minute. Assume time 0 is when the leak is discovered and negative time is before the leak is discovered.

Answer 1

For this case we can do the following:

y= mx +b

y= water (gallons) , x= time (minutes)

And on this case m =-3

We can use the point( x= 4, y= -12) and we have:

-12 = -3(4)+b

b= -12+12=0

And the equation would be given by:

y= -3x

And replacing we got:

y(-5) = 15

9= -3x, x= -3

y(6)= -3*6 = -18

y(10.5)= -3*10.5= -31.5

And the table is given by:

Time (minutes) Water (gallons)

-5 15

-3 9

4 -12

6 -18

10.5 -31.5