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The vertex form of the equation of a parabola is y=(x-3) squared + 36. What is the standard form of the question?
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The vertex form of the equation of a parabola is y=(x-3) squared + 36. What is the standard form of the question?

User Dapangmao
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2 Answers

4 votes
Final Answer: x^2 - 6x +45
1. (x-3)^2 --> x^2 -6x +9
2. x^2 - 6x +9 + 36

Final Answer x^2 - 6x + 45


User Bauervision
by
6.4k points
2 votes
standard form is y=ax^2+bx+c
just expand
y=(x-3)^2+36
y=(x-3)(x-3)+36
y=x^2-6x+9+36
y=x^2-6x+45
User Eng Cy
by
7.0k points
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