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Plans for a bridge are drawn on a coordinate grid. One girder of the bridge lies on the line y = 3x – 3. A perpendicular brace passes through the point (–7, 9). Write an equation of the line that contains the brace.

2 Answers

2 votes

Answer:

The answer is:


y = -(1)/(3)x +(20)/(3)

Explanation:

The slope of line y = 3x - 3 is k = 3, so the negative reciprocal is given by -1/k. Therefore the slope for the perpendicular equation is -1/3.

Now, the perpendicular equation passes through the point x = -7 y = 9, so you need to find b:


y = -(1)/(3)x +b // replace y = 9 and x = -7


9 = -(-7)/(3) +b // substract 7/3 in both sides


9 - (7)/(3) = (7)/(3) - (7)/(3) + b // solve


(20)/(3) = b

Replace b in the equation:


y = -(1)/(3)x +(20)/(3)

See the attachment.

Plans for a bridge are drawn on a coordinate grid. One girder of the bridge lies on-example-1
User Letitbe
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5.9k points
6 votes
Using the slope intercept formula, we conclude that the slope of line p:y=3x-3 is 3.Since line k is perpendicular to line p it must have a slope that is the negative reciprocal.Therefore the slope of line k is -1/3.Using the formula y-9=-1/3(x-(-7)) and doing the math we will end up with k:y=-1/3x+34/3
User Whihathac
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5.2k points