Mass A = 2000 kg
velocity A = 12 m/s (North)
Mass B= 4000 kg
Velocity B= -8 m/s (South)
We adopt that North is positive and South is negative.
Conservation of momentum (p)
• Pi = Pf
• ma * va + mb*vb = (ma+mb) Vf
Where Vf is the final velocity after the collision.
Replacing:
(2000* 12 ) + (4000*-8)= (2000+4000) vf
24,000- 32,000 = 6,000 vf
-8,000 = 6,000 vf
-8,000 / 6,000 = vf
vf = -1.3334 m/s
vf = 1.3334 m/s , South