Question

A spring of force constant 400 N/m is hung vertically from a ceiling. When a 32 kg mass hangs from the lower end of the spring, how far does the spring stretch?[Use g = 10 m/s2]

Answer 1

Answer:

The spring stretches by 0.8m

Step-by-step explanation:

The force constant, k = 400 N/m

The mass of the object that hangs from the lower end of the spring, m = 32kg

The acceleration due to gravity, g = 10 m/s²

The weight of the object, W = mg

W = 32 x 10

W = 320 N

The force applied to the spring, F = kx

where x is the extension of the spring

F = 400x

The weight of the object = The force applied to the spring

W = F

320 = 400x

Divide both sides by 400

x = 320/400

x = 0.8 m

The spring stretches by 0.8m