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The results of the math exam showed that three eighths of the students made an “A” and one third of them made a “B”. In total, how many students took the exam if the remaining 14 students made a grade other than an “A” or “B”?

User JBB
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1 Answer

9 votes
9 votes

3/8 = A

1/3 = B

So,


(3)/(8)+(1)/(3)=(3(3)+1(8))/(8(3))=(9+8)/(24)=(17)/(24)

17/24 got A or B.

So, the remaining "part" is WHOLE (1) minus 17/24, which is:

1 - 17/24 = 7/24

This "7/24" is equal to 14 sstudents, we need to find the total, which can be labeled as "x".

Thus we can write a ratio and solve:

if 7/24 is 14, then 1 is x


\begin{gathered} ((7)/(24))/(14)=(1)/(x) \\ (7)/(24)x=14 \\ x=(14)/((7)/(24)) \\ x=14\cdot(24)/(7) \\ x=2\cdot24 \\ x=48 \end{gathered}

Hence, total number of students is 48

User Rwilliams
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