Question

What are the domain and range of the function f(x)=- \/x+3 - 2?domain: -3

Answer 1

A. Domain: x<-2

Range: y> 1

Step-by-step explanation:

The inverse function f^-1(x) is a function whose domain and range are the range and domain of f(x) respectively.

Then, if the domain of f(x) is x>1, the range of the inverse function f^-1(x) is y > 1

And if the range of f(x) is y < -2, the domain of the f^-1(x) is x < -2

Therefore, the answer is:

A. Domain: x<-2

Range: y> 1

Answer 2

Given the function:

`f(x)=-\sqrt[]{x+3}-2`

So, the square root must be greater than or equal zero

The domain of the function is all the values that are possible for x

so,

`\begin{gathered} x+3\ge0 \\ x\ge-3 \end{gathered}`

So, the domain = x ≥ -3

The range is all the possible value of y when we substitute with x

So, the range will be:

`y\le-2`

So, the answer is option 3