What is the completely factored form of 9x2 + 24x + 16? (3x + 8)(3x + 2) (3x + 4)(3x + 4) (9x + 8)(x + 2) (9x + 4)(x + 4)

Question

asked Sep 24, 2018 151k views

2 Answers

Sam Bing · Answer 1 · 2018-09-27T23:33:28+0000

Answer: Option 2 is correct (3x+4)(3x+4)

Step-by-step explanation:

we have general form of quadratic equation
ax^2+bx+c

Given quadratic is
9x^2+24x+16

We will use the formula for discriminant which is
D=b^2-4ac

On comparing the given quadratic equation with the general quadratic equation we get a=9 , b=24,c=16

substituting the values in the formula for discriminant we will get

24^2-4(9)(16) =0

Now, to find x we have formula
$\frac{-b\pm√(D)} {2a}$

D=0 , b=24, c=16 substituting the values we will get

$x=(-24\pm0)/(2*9) =(-4)/(3),(-4)/(3)$

factors are
(x+(4)/(3))(x+(4)/(3))= (3x+4)(3x+4)