Question

In pea plants, tallness (T) is dominant to shortness (t). What is the predicted genotypic ratio of the offspring if a homozygous short plant is crossed with a heterozygous tall plant?

Answer 1

You would have to draw a punnet square to figure this one but here's my answer:

When I was done with the punnet square, I cross the letters between the two plants alleles
For example I cross T with t which makes Tt. Same with the next one, T and t which also makes Tt. Then I cross it with t and you get tt and the next one would also be tt.

So The answer is 50% Tt, and 50% tt

Answer 2

Genotypic ratio between Tt: tt will be 1:1

Step-by-step explanation:

It is given that allele "T" is dominant over allele "t"

Hence, the two parents between whom the cross is carried will have the following genotype -

a) Homozygous short plant - tt

b) Heterozygous tall plant - Tt

The cross between these two parents will produce the following offspring -

Tt x tt

Tt, Tt, tt, tt

So the genotypic ratio between Tt: tt will be 1:1